8/2(2+2) = ?

[Z-Man]

Moar math trolling.

Let's start with
1 = 1
Divide by three, explicitly on the left, symbolic on the right:
0.3333333333.... = 1/3
Multiply by three again:
0.9999999999... = 3/3 = 1
How can this be? That's clearly not equal.
(This can occupy forums filled with idiots who don't read half of what everyone before them wrote endlessly.)

And yeah, Titanoboa wins this thread easily.

[chrisd]

too easy, Z-man......

[kyle]

heh Z-man I saw the proof for this just about a month ago, But i forget the exact details.

[MaZuffeR]

s= 1+2+4+8+...
= 1+2*(1+2+4+8+...)
= 1+2*s

=> s= -1

[chah]

1.000000000000000000000000000000
-.999999999999999999999999999999
--------------------------------
0

[Jonathan]

Let's start with
1 = 1
Divide by three, explicitly on the left, symbolic on the right:
0.3333333333.... = 1/3
Multiply by three again:
0.9999999999... = 3/3 = 1
How can this be? That's clearly not equal.

Wait, what? How can 0.3333... = 1/3 in the first place? Obviously there can never be enough threes!

MaZuffer: For even more fun, change your base:
s=1+3+9+27+...
=1+3*(1+3+9+27+...)
=1+3*s
=-1/2

[Tank Program]

The TIs is exactly what I was thinking of.

Also, let's not forget all the wonderful proofs showing that -1 = 1 and the like...

There's also this wonderful proof for women = root evil floating around. And hell being endothermic. And the like.

[syllabear]

s= 1+2+4+8+...
= 1+2*(1+2+4+8+...)
= 1+2*s

=> s= -1

you simplified incorrectly

s=-1/2 lol how did you fail that

[Jonathan]

s= 1+2+4+8+...
= 1+2*(1+2+4+8+...)
= 1+2*s

=> s= -1

you simplified incorrectly

s=-1/2 lol how did you fail that

s=1+2*s not 0=1+2*s lol how did you fail that

[syllabear]

I can't help it, i only write = with nothing on one side if theres a 0

[Z-Man]

s= 1+2+4+8+...
= 1+2*(1+2+4+8+...)
= 1+2*s

=> s= -1

Things similar to that are, amazingly, considered true in physics. We call it "Analytic continuation" or "Regularization", the art of assigning numbers to usually infinite sums/integrals. Not this precise calculation, though. The singularity of [math]\sum_n q^n[/math] is the whole unit circle in the complex plane, can't pretend to continue around it.

[Cody <3]

BODMAS Method

8/2(2+2)=x
8/2(4)=x
4(4)=x
x=16

PEMDAS Method

8/2(2+2)=x
8/2(4)=x
4(4)=x(you do division first since it came first reading LTR and M & D have the same priority level)
x=16

Distributive Law

8/2(2+2)=x
8/2 x 2 = 8
8/2 x 2 = 8
8+8 = 16

Lalalala

remember, to do distributive law, you must take everything on the outside and multiply it by the inside for it to be correct.

Also quick note, it only equals 1 if the problem is written like this

8/[2(2+2)] = 1

or

Code: Select all

    
     8
  --------
   2(2+2) 

[INW]

Distribution LAW. Not operation.

order of operation, not order of properties cody...

[Olive]

is it:

(8/2)(2+2) =16

or

8/(2(2+2)) =1

[Phytotron]

Aren't you supposed to be in college? We were doing this stuff in, like, 7th grade.

5th grade.

Ah, so they accelerated math at the expense of arresting the rest of your educational and other development at the 4th grade. It all makes sense now.